LeetCode: Maximum Points You Can Obtain From Cards Solution

Approach

11 2 3 4 5 6 1
2_ _ _
3_ _ _
4_ _ _
5 _ _ _

Implementation

1/**
2 * @param {number[]} cardPoints
3 * @param {number} k
4 * @return {number}
5 */
6// sliding window
7var maxScore = function (cardPoints, k) {
8 const N = cardPoints.length
9 let res = (sum = cardPoints.slice(0, k).reduce((acc, el) => acc + el, 0))
10 for (let i = 1; i < k + 1; i++) {
11 sum += cardPoints[N - i] - cardPoints[k - i]
12 res = Math.max(res, sum)
13 }
14 return res
15}
16
17// memoized recursion (MLE)
18var maxScore = function (cardPoints, k) {
19 const N = cardPoints.length
20 const memo = Array.from({ length: N }, _ => Array(N).fill(undefined))
21
22 const recursion = (i, j, k) => {
23 if (i > N - 1 || j < 0 || k === 0) {
24 return 0
25 }
26 if (memo[i][j] !== undefined) {
27 return memo[i][j]
28 }
29 return (memo[i][j] = Math.max(
30 cardPoints[i] + recursion(i + 1, j, k - 1),
31 cardPoints[j] + recursion(i, j - 1, k - 1)
32 ))
33 }
34
35 return recursion(0, cardPoints.length - 1, k)
36}

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Tags

leetcode

array

dynamic programming

sliding window

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