LeetCode: Form Array By Concatenating Subarrays Of Another Array Solution

1const arrayEqual = (a, b) =>
2  a.length === b.length && a.every((el, i) => el === b[i])
3
4/**
5 * @param {number[][]} groups
6 * @param {number[]} nums
7 * @return {boolean}
8 */
9var canChoose = function (groups, nums) {
10  let i = 0
11
12  groupsLoop: for (const group of groups) {
13    for (let j = i; j < nums.length; j++) {
14      if (arrayEqual(nums.slice(j, j + group.length), group)) {
15        i = j + group.length
16        continue groupsLoop
17      }
18    }
19    return false
20  }
21
22  return true
23}