LeetCode: Reverse Prefix of Word Solution

Approach

If there is no index of

in , skip

Everything else is straight forward

Implementation

1var reversePrefix = function (word, ch) {
2  const indexOfCh = word.indexOf(ch)
3  return indexOfCh === -1
4    ? word
5    : word
6        .substring(0, indexOfCh + 1)
7        .split("")
8        .reverse()
9        .join("") + word.substring(indexOfCh + 1)
10}