# LeetCode: Summary Ranges Solution

*Straight forward checking*

## Approach

On each iteration, init

start

and end

to be equal to the iterated elementKeep assigning

end

while next element is greater than the current by one unitIf

start !== end

then it's a sub range## Implementation

1var summaryRanges = function (nums) {2 let start, end3 let res = []45 for (let i = 0; i < nums.length; i++) {6 start = end = nums[i]78 for (; nums[i + 1] === nums[i] + 1; i++) {9 end = nums[i + 1]10 }1112 res.push(start === end ? "" + start : start + "->" + end)13 }1415 return res16}

## Comments

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## Tags

leetcode

array

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