# LeetCode: Ugly Number Solution

*Recursively dividing*

## Approach

For negative number, always

false

Keep dividing

2, 3, 5

, the number is ugly if the result is 1

## Implementation

1var isUgly = function (n) {2 if (n <= 0) return false3 if (n % 2 === 0) return isUgly(n / 2)4 if (n % 3 === 0) return isUgly(n / 3)5 if (n % 5 === 0) return isUgly(n / 5)67 return n === 18}

## References

## Comments

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## Tags

leetcode

recursion

math

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