# LeetCode: Broken Calculator Solution

## Approach

Work backward

## Implementation

1/**2 * @param {number} X3 * @param {number} Y4 * @return {number}5 */6var brokenCalc = function (X, Y) {7 let res = 08 while (Y > X) {9 res++10 if (Y % 2 === 0) {11 Y /= 212 } else {13 Y++14 }15 }16 res += X - Y1718 return res19}

## Comments

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## Tags

leetcode

math

greedy

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